Question Number 222711 by sonukgindia last updated on 05/Jul/25
Answered by gabthemathguy25 last updated on 05/Jul/25
$$\left({ABC}\right)_{\mathrm{16}} =\mathrm{10}×\mathrm{16}^{\mathrm{2}} +\mathrm{11}×\mathrm{16}^{\mathrm{1}} +\mathrm{12}×\mathrm{16}^{\mathrm{0}} \\ $$$$\Rightarrow\mathrm{10}×\mathrm{256}+\mathrm{11}×\mathrm{16}+\mathrm{12}=\mathrm{2560}+\mathrm{176}+\mathrm{12}=\mathrm{2748} \\ $$$$\mathrm{its}\:\mathrm{1},\:\mathrm{2748}. \\ $$