Question Number 223000 by MrGaster last updated on 12/Jul/25
$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{\mathrm{1}}{{e}}\left(\frac{{n}+\mathrm{1}}{{n}}\right)^{{n}} \right)^{\left(−\mathrm{1}\right)^{{n}} } =\frac{{e}\centerdot\sqrt{\pi}\centerdot\sqrt[{\mathrm{6}}]{\mathrm{2}}}{{A}^{\mathrm{6}} } \\ $$
Commented by MathematicalUser2357 last updated on 22/Jul/25
$$\boldsymbol{{no}}!!!\:{you}\:{catched}\:{question}#\mathrm{223000} \\ $$
Answered by MrGaster last updated on 12/Jul/25
