Question Number 223908 by yerlow3 last updated on 09/Aug/25
Answered by dionigi last updated on 10/Aug/25
$$ \\ $$$${ABCD}\:{should}\:{be}\:{a}\:{regular}\:{hemi}−{hexagon} \\ $$$${r}\:=\:{PA}\:=\:{PB}\:=\:{PC}\:=\:{PD} \\ $$$${r}\:=\:{DA}\:=\:{AB}\:=\:{BC} \\ $$$${and}\:{P}\:{the}\:{center}\:{of}\:{thr}\:{circle} \\ $$$$ \\ $$
Commented by MathematicalUser2357 last updated on 11/Aug/25
$$ \\ $$$$ \\ $$