Menu Close

a-b-c-gt-0-a-b-c-2-abc-prove-that-1-7-a-1-7-b-1-7-c-1-




Question Number 224016 by hardmath last updated on 14/Aug/25
a,b,c>0  a+b+c+2=abc  prove that:   (1/( (√(7+a)))) + (1/( (√(7+b)))) + (1/( (√(7+c)))) ≤ 1
$$\mathrm{a},\mathrm{b},\mathrm{c}>\mathrm{0} \\ $$$$\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{2}=\mathrm{abc} \\ $$$$\mathrm{prove}\:\mathrm{that}:\:\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}+\mathrm{a}}}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}+\mathrm{b}}}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}+\mathrm{c}}}\:\leqslant\:\mathrm{1} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *