Question Number 224030 by behi834171 last updated on 15/Aug/25
Answered by Rasheed.Sindhi last updated on 15/Aug/25
$${x}^{\mathrm{3}} \geqslant\mathrm{18}\Rightarrow{x}\neq\mathrm{1},\mathrm{2} \\ $$$$\mathrm{3}^{\mathrm{3}} =\mathrm{3}^{\mathrm{3}} +\mathrm{17}\:× \\ $$$$\mathrm{3}^{\mathrm{4}} =\mathrm{4}^{\mathrm{3}} +\mathrm{17}\checkmark \\ $$$${x}=\mathrm{4} \\ $$$$\mathrm{3}^{{x}} >{x}^{\mathrm{3}} +\mathrm{17}\:{for}\:{x}>\mathrm{4} \\ $$