Question-224153

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Question Number 224153 by fantastic last updated on 23/Aug/25

Commented by fantastic last updated on 23/Aug/25

$$\measuredangle{BOC}=\mathrm{80}^{\mathrm{0}} \\ $$$$\measuredangle{BAC}=? \\ $$

Commented by mr W last updated on 23/Aug/25

if O is orthocenter, then ∠BAC+∠BOC=180°

$${if}\:{O}\:{is}\:{orthocenter},\:{then} \\ $$$$\angle{BAC}+\angle{BOC}=\mathrm{180}° \\ $$

Commented by fantastic last updated on 23/Aug/25

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Commented by A5T last updated on 23/Aug/25

If O is orthocentre, ∡BOC has to be greater than 90° ∡BOC=∡OFB+∡OBF=90°+∡OBF>90°

$$\mathrm{If}\:\mathrm{O}\:\mathrm{is}\:\mathrm{orthocentre},\:\measuredangle\mathrm{BOC}\:\mathrm{has}\:\mathrm{to}\:\mathrm{be}\:\mathrm{greater}\:\mathrm{than} \\ $$$$\mathrm{90}° \\ $$$$\measuredangle\mathrm{BOC}=\measuredangle\mathrm{OFB}+\measuredangle\mathrm{OBF}=\mathrm{90}°+\measuredangle\mathrm{OBF}>\mathrm{90}° \\ $$

Commented by fantastic last updated on 23/Aug/25