Question Number 224213 by fantastic last updated on 25/Aug/25
Commented by fantastic last updated on 25/Aug/25
![The resultant of two forces Pand Q inclined at a certain angle is R. The angle betweenR and P is θ. If the vector P is changed to (P+R)[Direction not changed ] show that the resultant of the forces (P+R) and Q will act at an angle (θ/2) with the force (P+Q)](https://www.tinkutara.com/question/Q224216.png)
$$ \\ $$$$\mathrm{The}\:\mathrm{resultant}\:\mathrm{of}\:\mathrm{two}\:\mathrm{forces}\: \\ $$$$\mathrm{Pand}\:\mathrm{Q}\:\mathrm{inclined}\:\mathrm{at}\:\mathrm{a}\:\mathrm{certain} \\ $$$$\mathrm{angle}\:\mathrm{is}\:\mathrm{R}.\:\mathrm{The}\:\mathrm{angle}\:\: \\ $$$$\mathrm{betweenR}\:\mathrm{and}\:\mathrm{P}\:\mathrm{is}\:\theta.\:\mathrm{If}\:\mathrm{the} \\ $$$$\:\mathrm{vector}\:\mathrm{P}\:\mathrm{is} \\ $$$$\mathrm{changed}\:\mathrm{to}\:\left(\mathrm{P}+\mathrm{R}\right)\left[{Direction}\:{not}\:{changed}\:\right] \\ $$$$\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{the}\:\mathrm{resultant}\:\mathrm{of}\:\mathrm{the}\:\mathrm{forces} \\ $$$$\left(\mathrm{P}+\mathrm{R}\right)\:\mathrm{and}\:\mathrm{Q}\:\mathrm{will}\:\mathrm{act}\:\mathrm{at}\:\mathrm{an} \\ $$$$\mathrm{angle}\:\frac{\theta}{\mathrm{2}}\:\mathrm{with}\:\mathrm{the}\:\mathrm{force}\:\left(\mathrm{P}+\mathrm{Q}\right) \\ $$
Answered by fantastic last updated on 25/Aug/25
