Question Number 224314 by Matica last updated on 01/Sep/25
$${solve}\:\sqrt[{\mathrm{3}}]{\mathrm{1}−\sqrt{{x}}}=\mathrm{2} \\ $$
Commented by Ghisom_ last updated on 01/Sep/25
$$\mathrm{no}\:\mathrm{solution}\:\in\mathbb{C} \\ $$$$\mathrm{1}−\sqrt{{x}}=\mathrm{8} \\ $$$$\sqrt{{x}}=−\mathrm{7}=\mathrm{7e}^{\mathrm{i}\pi} \\ $$$$\mathrm{but}\:\mathrm{for}\:{x}\in\mathbb{C}:\:−\frac{\pi}{\mathrm{2}}<\mathrm{arg}\:\sqrt{{x}}\:\leqslant\frac{\pi}{\mathrm{2}} \\ $$