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K-0-sinx-coshx-e-2x-e-4x-dx-




Question Number 224771 by mnjuly1970 last updated on 03/Oct/25
    K=∫_0 ^( ∞) ((sinx)/(coshx)) (e^(−2x) −e^(−4x) )dx=?
$$ \\ $$$$\:\:{K}=\int_{\mathrm{0}} ^{\:\infty} \frac{{sinx}}{{coshx}}\:\left({e}^{−\mathrm{2}{x}} −{e}^{−\mathrm{4}{x}} \right){dx}=?\:\:\:\:\: \\ $$$$\:\: \\ $$

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