Question-226409

Question Number 226409 by hardmath last updated on 27/Nov/25

Answered by fantastic2 last updated on 27/Nov/25

Commented by fantastic2 last updated on 27/Nov/25

α+90^0 +70^0 =180^0 ⇒α=20^0 β=90^0 ⇒γ=270^0 60^0 +γ+α+θ=360^0 ⇒θ=10^0 θ+90^0 +φ=180^0 ⇒φ=80^0

$$\alpha+\mathrm{90}^{\mathrm{0}} +\mathrm{70}^{\mathrm{0}} =\mathrm{180}^{\mathrm{0}} \\ $$$$\Rightarrow\alpha=\mathrm{20}^{\mathrm{0}} \\ $$$$\beta=\mathrm{90}^{\mathrm{0}} \Rightarrow\gamma=\mathrm{270}^{\mathrm{0}} \\ $$$$\mathrm{60}^{\mathrm{0}} +\gamma+\alpha+\theta=\mathrm{360}^{\mathrm{0}} \Rightarrow\theta=\mathrm{10}^{\mathrm{0}} \\ $$$$\theta+\mathrm{90}^{\mathrm{0}} +\phi=\mathrm{180}^{\mathrm{0}} \\ $$$$\Rightarrow\phi=\mathrm{80}^{\mathrm{0}} \\ $$$$ \\ $$

Answered by mr W last updated on 27/Nov/25