Question Number 226447 by Tawa11 last updated on 29/Nov/25
Commented by Tawa11 last updated on 29/Nov/25
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{semi}\:\mathrm{circle}. \\ $$
Answered by mr W last updated on 29/Nov/25
Commented by mr W last updated on 29/Nov/25
$$\:=\frac{\mathrm{13}{r}}{\mathrm{2}}+\frac{\mathrm{14}{r}}{\mathrm{2}}=\frac{\sqrt{\left(\mathrm{13}+\mathrm{14}+\mathrm{15}\right)\left(−\mathrm{13}+\mathrm{14}+\mathrm{15}\right)\left(\mathrm{13}−\mathrm{14}+\mathrm{15}\right)\left(\mathrm{13}+\mathrm{14}−\mathrm{15}\right)}}{\mathrm{4}} \\ $$$$\Rightarrow{r}=\frac{\sqrt{\mathrm{42}×\mathrm{16}×\mathrm{14}×\mathrm{12}}}{\mathrm{2}\left(\mathrm{13}+\mathrm{14}\right)}=\frac{\mathrm{56}}{\mathrm{9}} \\ $$
Commented by Tawa11 last updated on 29/Nov/25
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{appreciate}. \\ $$