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Question-226991




Question Number 226991 by Spillover last updated on 24/Dec/25
Answered by mehdee7396 last updated on 24/Dec/25
AB=39  &  AC=28⇒∡B⋍((7π)/(36))  &  ∡C⋍((11π)/(36))  S=(1/2)×28×39−(((36π)/4)+((49π)/2)+((64π)/2)×((11π)/2))−(((25π)/2)+((64π)/2)+((49π)/2)×((7π)/2))
$${AB}=\mathrm{39}\:\:\&\:\:{AC}=\mathrm{28}\Rightarrow\measuredangle{B}\backsimeq\frac{\mathrm{7}\pi}{\mathrm{36}}\:\:\&\:\:\measuredangle{C}\backsimeq\frac{\mathrm{11}\pi}{\mathrm{36}} \\ $$$${S}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{28}×\mathrm{39}−\left(\frac{\mathrm{36}\pi}{\mathrm{4}}+\frac{\mathrm{49}\pi}{\mathrm{2}}+\frac{\mathrm{64}\pi}{\mathrm{2}}×\frac{\mathrm{11}\pi}{\mathrm{2}}\right)−\left(\frac{\mathrm{25}\pi}{\mathrm{2}}+\frac{\mathrm{64}\pi}{\mathrm{2}}+\frac{\mathrm{49}\pi}{\mathrm{2}}×\frac{\mathrm{7}\pi}{\mathrm{2}}\right) \\ $$

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