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umm-hi-




Question Number 227194 by fantastic2 last updated on 05/Jan/26
umm.... hi
$${umm}….\:{hi} \\ $$
Commented by fantastic2 last updated on 05/Jan/26
((∣x∣−2)/(∣x∣−3))≥0  x∈?
$$\frac{\mid{x}\mid−\mathrm{2}}{\mid{x}\mid−\mathrm{3}}\geqslant\mathrm{0} \\ $$$${x}\in? \\ $$
Commented by Frix last updated on 05/Jan/26
1.  ∣x∣−2>0∧∣x∣−3>0  ∣x∣≥2∧∣x∣>3  x<−3∨x>3    2.  ∣x∣−2≤0∧∣x∣−3<0  ∣x∣≤2∧∣x∣<3  −2≤x≤2    x<−3∨−2≤x≤2∨3<x
$$\mathrm{1}. \\ $$$$\mid{x}\mid−\mathrm{2}>\mathrm{0}\wedge\mid{x}\mid−\mathrm{3}>\mathrm{0} \\ $$$$\mid{x}\mid\geqslant\mathrm{2}\wedge\mid{x}\mid>\mathrm{3} \\ $$$${x}<−\mathrm{3}\vee{x}>\mathrm{3} \\ $$$$ \\ $$$$\mathrm{2}. \\ $$$$\mid{x}\mid−\mathrm{2}\leqslant\mathrm{0}\wedge\mid{x}\mid−\mathrm{3}<\mathrm{0} \\ $$$$\mid{x}\mid\leqslant\mathrm{2}\wedge\mid{x}\mid<\mathrm{3} \\ $$$$−\mathrm{2}\leqslant{x}\leqslant\mathrm{2} \\ $$$$ \\ $$$${x}<−\mathrm{3}\vee−\mathrm{2}\leqslant{x}\leqslant\mathrm{2}\vee\mathrm{3}<{x} \\ $$

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