6y-3-dx-2x-dy-x-1-dx-

Question Number 131194 by john_santu last updated on 02/Feb/21

$$\:\mathrm{6}{y}^{\mathrm{3}} \:{dx}\:+\:\mathrm{2}{x}\:{dy}\:=\:\left({x}+\mathrm{1}\right)\:{dx}\: \\ $$