Question Number 15288 by ajfour last updated on 09/Jun/17
Commented by ajfour last updated on 09/Jun/17
![x^2 −6x+5+[x]=0 ⇒ (x−3)^2 =4−[x] .](https://www.tinkutara.com/question/Q15289.png)
$$\:{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{5}+\left[{x}\right]=\mathrm{0} \\ $$$$\Rightarrow\:\left({x}−\mathrm{3}\right)^{\mathrm{2}} =\mathrm{4}−\left[{x}\right]\:. \\ $$