3-7-1-2-ln-u-1-u-1-1-2-ln-u-2-1-

Question Number 84328 by sahnaz last updated on 11/Mar/20

$$\frac{\mathrm{3}}{\mathrm{7}}×\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\left[\frac{\mathrm{u}−\mathrm{1}}{\mathrm{u}+\mathrm{1}}\right]−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\left[\mathrm{u}^{\mathrm{2}} −\mathrm{1}\right] \\ $$

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