Question Number 150425 by saly last updated on 12/Aug/21

Commented by saly last updated on 12/Aug/21

$$\:\:\:{Merci}\:\:{beaucoup} \\ $$
Commented by saly last updated on 12/Aug/21

$$\:{help}\:{me} \\ $$
Commented by mr W last updated on 12/Aug/21

$$\theta=\mathrm{tan}^{−\mathrm{1}} \frac{{a}}{{g}} \\ $$
Commented by saly last updated on 12/Aug/21
