Question Number 171761 by Mikenice last updated on 20/Jun/22
$${solve}: \\ $$$$\frac{{sin}\left(\mathrm{10}+{x}\right)}{{sin}\left(\mathrm{13}+{x}\right)}=\frac{{sin}\mathrm{27}{sin}\mathrm{39}}{{sin}\mathrm{24}{sin}\mathrm{57}} \\ $$
solve-sin-10-x-sin-13-x-sin27sin39-sin24sin57-