Question Number 178200 by Shrinava last updated on 13/Oct/22
Answered by Frix last updated on 14/Oct/22
![f(x)=e^(2x/3) f(x)×f(x/2)=e^(2x/3) e^(x/3) =e^x Ω=−∞ [limit doesn′t exist]](https://www.tinkutara.com/question/Q178214.png)
$${f}\left({x}\right)=\mathrm{e}^{\mathrm{2}{x}/\mathrm{3}} \\ $$$${f}\left({x}\right)×{f}\left({x}/\mathrm{2}\right)=\mathrm{e}^{\mathrm{2}{x}/\mathrm{3}} \mathrm{e}^{{x}/\mathrm{3}} =\mathrm{e}^{{x}} \\ $$$$\Omega=−\infty\:\left[\mathrm{limit}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{exist}\right] \\ $$