Question Number 183767 by Tawa11 last updated on 29/Dec/22
Answered by MikeH last updated on 30/Dec/22
![P_0 = 1.3 × 10^5 N m^(−2) P_(gauge) = ρgh + P_0 ⇒ P_(gauge) =[ (1000)(9.8)(10) + 1.3×10^5 ]N m^(−2) ⇒ P_(gauge ) = 2.28 × 10^5 N m^(−2)](https://www.tinkutara.com/question/Q183805.png)
$${P}_{\mathrm{0}} \:=\:\mathrm{1}.\mathrm{3}\:×\:\mathrm{10}^{\mathrm{5}} \:\mathrm{N}\:\mathrm{m}^{−\mathrm{2}} \\ $$$$\mathrm{P}_{\mathrm{gauge}} \:=\:\rho\mathrm{g}{h}\:+\:{P}_{\mathrm{0}} \\ $$$$\Rightarrow\:{P}_{\mathrm{gauge}} \:=\left[\:\left(\mathrm{1000}\right)\left(\mathrm{9}.\mathrm{8}\right)\left(\mathrm{10}\right)\:+\:\mathrm{1}.\mathrm{3}×\mathrm{10}^{\mathrm{5}} \right]\mathrm{N}\:\mathrm{m}^{−\mathrm{2}} \\ $$$$\Rightarrow\:{P}_{\mathrm{gauge}\:} \:=\:\mathrm{2}.\mathrm{28}\:×\:\mathrm{10}^{\mathrm{5}} \:\mathrm{N}\:\mathrm{m}^{−\mathrm{2}} \\ $$
Commented by Tawa11 last updated on 30/Dec/22
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$