Question Number 183803 by Ar Brandon last updated on 30/Dec/22
Answered by mr W last updated on 30/Dec/22
Commented by mr W last updated on 30/Dec/22
$$\Delta{AEF}\equiv\Delta{AEF}\:' \\ $$$${x}=\mathrm{180}−\mathrm{70}−\mathrm{45}=\mathrm{65}° \\ $$
Commented by Ar Brandon last updated on 30/Dec/22
Thank you Sir