Question Number 196525 by Mastermind last updated on 26/Aug/23
Answered by mr W last updated on 27/Aug/23
![(√(m^2 +1))>(√m^2 )=m (√(m^2 +1))<(√(m^2 +2m+1))=(√((m+1)^2 ))=m+1 since m<(√(m^2 +1))<m+1, ⇒[(√(m^2 +1))]=m](https://www.tinkutara.com/question/Q196545.png)
$$\sqrt{{m}^{\mathrm{2}} +\mathrm{1}}>\sqrt{{m}^{\mathrm{2}} }={m} \\ $$$$\sqrt{{m}^{\mathrm{2}} +\mathrm{1}}<\sqrt{{m}^{\mathrm{2}} +\mathrm{2}{m}+\mathrm{1}}=\sqrt{\left({m}+\mathrm{1}\right)^{\mathrm{2}} }={m}+\mathrm{1} \\ $$$${since}\:{m}<\sqrt{{m}^{\mathrm{2}} +\mathrm{1}}<{m}+\mathrm{1}, \\ $$$$\Rightarrow\left[\sqrt{{m}^{\mathrm{2}} +\mathrm{1}}\right]={m} \\ $$
Commented by Mastermind last updated on 27/Aug/23
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much} \\ $$