Question-213668

Question Number 213668 by mr W last updated on 13/Nov/24

Commented by mr W last updated on 13/Nov/24

$${find}\:{shaded}\:{area} \\ $$

Answered by BHOOPENDRA last updated on 13/Nov/24

Commented by BHOOPENDRA last updated on 13/Nov/24

$$\left(\mathrm{36}+\mathrm{12}\right)−\left(\mathrm{4}+\mathrm{12}\right)=\mathrm{32} \\ $$$${shaded}\:{area}\:=\mathrm{32}+\mathrm{12}=\mathrm{44} \\ $$

Commented by mr W last updated on 13/Nov/24

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Answered by mr W last updated on 13/Nov/24

Commented by mr W last updated on 13/Nov/24

$${A}+\mathrm{12}={A}+{B}\:\Rightarrow{B}=\mathrm{12} \\ $$$$\frac{{A}}{{B}}=\frac{\mathrm{12}}{\mathrm{4}}\:\Rightarrow{A}=\mathrm{3}{B}=\mathrm{36} \\ $$$${A}+{B}=\mathrm{12}+\mathrm{4}+{C} \\ $$$$\Rightarrow{C}=\mathrm{12}+\mathrm{36}−\mathrm{16}=\mathrm{32} \\ $$$${shaded}=\mathrm{32}+\mathrm{12}=\mathrm{44} \\ $$

Commented by BHOOPENDRA last updated on 13/Nov/24

$${Nice} \\ $$

Answered by A5T last updated on 13/Nov/24

Commented by A5T last updated on 13/Nov/24

$$\mathrm{12}+\mathrm{4}=\mathrm{4}+{x}\Rightarrow{x}=\mathrm{12} \\ $$$$\mathrm{12}+\mathrm{3}{x}=\mathrm{4}+\left[{shaded}\:{area}\right] \\ $$$$\Rightarrow\left[{shaded}\:{area}\right]=\mathrm{44} \\ $$

Answered by MathematicalUser2357 last updated on 14/Nov/24

$$\mathrm{44}\: \\ $$

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