Question Number 213738 by Spillover last updated on 15/Nov/24
Answered by MrGaster last updated on 03/Feb/25
$$=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}^{\mathrm{2}} \mathrm{2}+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} }{\mathrm{2}^{{n}} {n}^{\mathrm{2}} } \\ $$