Question Number 215004 by efronzo1 last updated on 25/Dec/24
Commented by mr W last updated on 26/Dec/24
$$\left({xy}+\frac{\lambda^{\mathrm{2}} }{{xy}}\right)_{{min}} =\frac{\mathrm{1}}{\mathrm{4}}+\mathrm{4}\lambda^{\mathrm{2}} \\ $$
Commented by efronzo1 last updated on 27/Dec/24
$$\mathrm{for}\:\mathrm{x}\:=\:\mathrm{y}\:=\:?\:\mathrm{sir} \\ $$
Commented by mr W last updated on 27/Dec/24
$${yes} \\ $$