Question Number 216607 by Tawa11 last updated on 12/Feb/25
Answered by Rasheed.Sindhi last updated on 12/Feb/25
$$\mathrm{4}{x}^{\mathrm{2}} +{bx}−\mathrm{45}=\left({hx}+{k}\right)\left({x}+{j}\right);{h},{k},{j}\in\mathbb{Z} \\ $$$$\:\:\:\:\:\:\:\:={hx}^{\mathrm{2}} +\left({hj}+{k}\right){x}+{kj} \\ $$$${kj}=−\mathrm{45}\Rightarrow{j}=−\frac{\mathrm{45}}{{k}} \\ $$$$\frac{\mathrm{45}}{{k}}=−{j}\:\in\:\mathbb{Z}\:\rightarrow\left({D}\right) \\ $$
Commented by Tawa11 last updated on 12/Feb/25
$$\mathrm{Thanks}\:\mathrm{sir},\:\mathrm{I}\:\mathrm{appreciate}. \\ $$