Question Number 217991 by yassin last updated on 25/Mar/25
$${x}^{\mathrm{2}} +\mathrm{3}=\mathrm{0} \\ $$$${x}^{\mathrm{2}} +\mathrm{5}=\mathrm{3} \\ $$
Answered by shunmisaki007 last updated on 25/Mar/25
$${x}^{\mathrm{2}} +\mathrm{3}=\mathrm{0} \\ $$$${x}^{\mathrm{2}} −\left(\sqrt{\mathrm{3}}{i}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${x}=\sqrt{\mathrm{3}}{i},\:{x}=−\sqrt{\mathrm{3}}{i}\:\bigstar \\ $$$$ \\ $$$${x}^{\mathrm{2}} +\mathrm{5}=\mathrm{3} \\ $$$${x}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$${x}^{\mathrm{2}} −\left(\sqrt{\mathrm{2}}{i}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${x}=\sqrt{\mathrm{2}}{i},\:{x}=−\sqrt{\mathrm{2}}{i}\:\bigstar \\ $$