Question Number 218557 by efronzo1 last updated on 12/Apr/25
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Commented by efronzo1 last updated on 12/Apr/25
Answered by A5T last updated on 12/Apr/25
$$\mathrm{R}×\sqrt{\left(\mathrm{R}+\mathrm{6}\right)^{\mathrm{2}} −\left(\mathrm{R}−\mathrm{6}\right)^{\mathrm{2}} }=\mathrm{243} \\ $$$$\Rightarrow\mathrm{R}\sqrt{\mathrm{24R}}=\mathrm{243}\Rightarrow\mathrm{R}^{\mathrm{3}} =\frac{\mathrm{243}^{\mathrm{2}} }{\mathrm{24}}\Rightarrow\mathrm{R}=\frac{\mathrm{27}}{\mathrm{2}} \\ $$