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Question-219086




Question Number 219086 by Spillover last updated on 19/Apr/25
Answered by Spillover last updated on 19/Apr/25
 v= [axbxsin60°]l  V=[2x5xsin 60°]×10 cm^3
v= [axbxsin60°]l
V=[2x5xsin 60°]×10 cm^3
Answered by mr W last updated on 19/Apr/25
V=(1/2)(5+3)×2 sin 60°×10=40(√3) cm^3
$${V}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{5}+\mathrm{3}\right)×\mathrm{2}\:\mathrm{sin}\:\mathrm{60}°×\mathrm{10}=\mathrm{40}\sqrt{\mathrm{3}}\:{cm}^{\mathrm{3}} \\ $$

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