Question Number 219503 by Rojarani last updated on 27/Apr/25
Answered by Frix last updated on 27/Apr/25
$$\sqrt{\mathrm{4}{x}}+\sqrt{\mathrm{4}{x}−\mathrm{4}}+\sqrt{\mathrm{4}{x}−\mathrm{8}}=\sqrt{{x}+\mathrm{1}}+\sqrt{{x}+\mathrm{5}}+\sqrt{{x}+\mathrm{9}} \\ $$$$\sqrt{\mathrm{4}{x}}=\sqrt{{x}+\mathrm{9}}\:\Rightarrow\:{x}=\mathrm{3} \\ $$$$\sqrt{\mathrm{4}{x}−\mathrm{4}}=\sqrt{{x}+\mathrm{5}}\:\Rightarrow\:{x}=\mathrm{3} \\ $$$$\sqrt{\mathrm{4}{x}−\mathrm{8}}=\sqrt{{x}+\mathrm{1}}\:\Rightarrow\:{x}=\mathrm{3} \\ $$