Question Number 219710 by SdC355 last updated on 01/May/25
$$\int_{\rho} ^{\:\infty} \:\frac{{e}^{{r}} \centerdot\Gamma\left(\mathrm{0},{r}\right)}{{r}}\:\mathrm{d}{r}=?? \\ $$$$\Gamma\left(\alpha,{r}\right)=\frac{\mathrm{1}}{\Gamma\left(\mathrm{1}−\alpha\right)}\centerdot\int_{\mathrm{0}} ^{\:\infty} \:\frac{\theta\left({s}−\mathrm{1}\right)}{{s}\left({s}−\mathrm{1}\right)^{\alpha} }{e}^{−{sr}} \mathrm{d}{s} \\ $$