Question Number 220250 by Spillover last updated on 10/May/25
Answered by mr W last updated on 10/May/25
$${as}\:{proved}\:{in}\:{Q}\mathrm{220231}: \\ $$$${R}={a}+{b} \\ $$$${S}=\frac{\pi}{\mathrm{2}}\left({R}^{\mathrm{2}} −{a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right)=\pi{ab} \\ $$
Commented by fantastic last updated on 10/May/25
$${where}\:{are}\:{you}\:{from} \\ $$
Answered by Spillover last updated on 12/May/25
Answered by Spillover last updated on 12/May/25
