Question Number 220495 by Jubr last updated on 13/May/25
Commented by mr W last updated on 14/May/25
$${i}\:{guess}\:{even}\:{you}\:{also}\:{don}'{t}\:{know} \\ $$$${what}\:{the}\:{question}\:{means}\:{with}\:{all} \\ $$$${the}\:{arrows}.\:{when}\:{the}\:{question}\:{is} \\ $$$${unclear},\:{it}\:{can}\:{not}\:{be}\:{solved}.\:{so} \\ $$$${please}\:{make}\:{your}\:{question}\:{clear}\:{at} \\ $$$${first}. \\ $$
Commented by Jubr last updated on 14/May/25
Commented by mr W last updated on 14/May/25
Commented by mr W last updated on 14/May/25
$${the}\:{figure}\:{has}\:{still}\:{no}\:{solution}!\:{it} \\ $$$${is}\:{exactly}\:{the}\:{same}\:{as}\:{the}\:{one}\:{above}. \\ $$$${you}\:{must}\:{add}\:{additional}\:{conditions}: \\ $$$${e}.{g}.\:{RQ}//{PY},\:{PQ}//{ZY} \\ $$
Commented by mr W last updated on 14/May/25
$$\frac{{XR}}{\mathrm{4}}=\frac{\mathrm{8}}{\mathrm{6}}\:\Rightarrow{XR}=\frac{\mathrm{16}}{\mathrm{3}} \\ $$$$\frac{{y}}{\mathrm{10}}=\frac{\mathrm{8}}{\mathrm{8}+\mathrm{6}}\:\Rightarrow{y}=\frac{\mathrm{40}}{\mathrm{7}} \\ $$$$\frac{{x}}{\mathrm{6}}=\frac{\frac{\mathrm{16}}{\mathrm{3}}+\mathrm{4}}{\mathrm{8}}\:\Rightarrow{x}=\mathrm{7} \\ $$$$\frac{\mathrm{16}}{\mathrm{3}}×{z}^{\mathrm{2}} +\mathrm{4}×\mathrm{8}^{\mathrm{2}} =\left(\frac{\mathrm{16}}{\mathrm{3}}+\mathrm{4}\right)\left(\mathrm{7}^{\mathrm{2}} +\frac{\mathrm{16}}{\mathrm{3}}×\mathrm{4}\right) \\ $$$$\Rightarrow{z}=\frac{\sqrt{\mathrm{2703}}}{\mathrm{6}}\approx\mathrm{8}.\mathrm{665} \\ $$
Commented by Jubr last updated on 20/May/25
$${Thank}\:{you}\:{sir}. \\ $$