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Question-221056




Question Number 221056 by fantastic last updated on 23/May/25
Answered by Frix last updated on 24/May/25
Area of trapezoid =((16+22)/2)h=19h  h=(√(4^2 −(((22−16)/2))^2 ))=(√7)  r=((√7)/2)  Shaded area = 19(√7)−((7π)/4)
$$\mathrm{Area}\:\mathrm{of}\:\mathrm{trapezoid}\:=\frac{\mathrm{16}+\mathrm{22}}{\mathrm{2}}{h}=\mathrm{19}{h} \\ $$$${h}=\sqrt{\mathrm{4}^{\mathrm{2}} −\left(\frac{\mathrm{22}−\mathrm{16}}{\mathrm{2}}\right)^{\mathrm{2}} }=\sqrt{\mathrm{7}} \\ $$$${r}=\frac{\sqrt{\mathrm{7}}}{\mathrm{2}} \\ $$$$\mathrm{Shaded}\:\mathrm{area}\:=\:\mathrm{19}\sqrt{\mathrm{7}}−\frac{\mathrm{7}\pi}{\mathrm{4}} \\ $$

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