Question Number 221288 by alcohol last updated on 29/May/25
Answered by mahdipoor last updated on 29/May/25
$$\frac{{x}+\frac{{x}+…}{\mathrm{1}+…}}{\mathrm{1}+\frac{{x}+…}{\mathrm{1}+…}}={A}=\frac{{x}+{A}}{\mathrm{1}+{A}}\:\Rightarrow{A}=\sqrt{{x}} \\ $$$$\int\sqrt{{x}}{dx}=\frac{\mathrm{2}}{\mathrm{3}}{x}^{\mathrm{3}/\mathrm{2}} +{C} \\ $$$$ \\ $$