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Question-221707




Question Number 221707 by Tawa11 last updated on 09/Jun/25
Commented by Tawa11 last updated on 09/Jun/25
In the ∆ABC |AB|=|BC|=|AC|=K, Area of  the shaded ∆ is (225/K )cm².  Find the height of the triangle ∆ABC.
In the ∆ABC |AB|=|BC|=|AC|=K, Area of
the shaded ∆ is (225/K )cm².
Find the height of the triangle ∆ABC.
Commented by fantastic last updated on 09/Jun/25
please clarify the drawing and the statement
$${please}\:{clarify}\:{the}\:{drawing}\:{and}\:{the}\:{statement} \\ $$
Commented by Tawa11 last updated on 09/Jun/25
Commented by Tawa11 last updated on 09/Jun/25
This is what they drew again.
$$\mathrm{This}\:\mathrm{is}\:\mathrm{what}\:\mathrm{they}\:\mathrm{drew}\:\mathrm{again}. \\ $$
Commented by Tawa11 last updated on 09/Jun/25
The height of triangle can be found using Viviani's theorem. They mention this too.
Commented by fantastic last updated on 09/Jun/25
is there anything given about the size of the circles?
$${is}\:{there}\:{anything}\:{given}\:{about}\:{the}\:{size}\:{of}\:{the}\:{circles}? \\ $$
Commented by Tawa11 last updated on 09/Jun/25
OM is perpendicular to AC And ON is perpendicular to BC
Commented by fantastic last updated on 09/Jun/25
i will try
$${i}\:{will}\:{try} \\ $$
Commented by Tawa11 last updated on 09/Jun/25
Thanks sir.
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$
Commented by fantastic last updated on 09/Jun/25
the question itself is wrong .just think   the virtically opposite angle of ∡NO .. is 90^(0 )   how is that possible??
$${the}\:{question}\:{itself}\:{is}\:{wrong}\:.{just}\:{think}\: \\ $$$${the}\:{virtically}\:{opposite}\:{angle}\:{of}\:\measuredangle{NO}\:..\:{is}\:\mathrm{90}^{\mathrm{0}\:} \\ $$$${how}\:{is}\:{that}\:{possible}?? \\ $$
Commented by Tawa11 last updated on 09/Jun/25
Commented by Tawa11 last updated on 09/Jun/25
Commented by Tawa11 last updated on 09/Jun/25
Is this correct?
$$\mathrm{Is}\:\mathrm{this}\:\mathrm{correct}? \\ $$
Answered by fantastic last updated on 09/Jun/25

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