Question Number 223216 by Ari last updated on 18/Jul/25
Answered by som(math1967) last updated on 18/Jul/25
$${let}\:{alcohol}=\mathrm{4}{xl},\:{water}=\mathrm{3}{xl} \\ $$$$\:\therefore\:\frac{\mathrm{4}{x}}{\mathrm{3}{x}+\mathrm{7}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\Rightarrow\mathrm{16}{x}=\mathrm{9}{x}+\mathrm{21} \\ $$$$\Rightarrow\mathrm{7}{x}=\mathrm{21}\Rightarrow{x}=\mathrm{3} \\ $$$$\:{amount}\:{of}\:{alcohol}=\mathrm{4}×\mathrm{3}=\mathrm{12}{l} \\ $$
Answered by Rasheed.Sindhi last updated on 18/Jul/25
$${Before}\: \\ $$$${alcohol}\::\:\mathrm{4}{x} \\ $$$${water}:\:\:\:\:\mathrm{3}{x} \\ $$$${After}\:{adding}\:\mathrm{7}\:{liters}\:{water} \\ $$$${alcohol}:\:\mathrm{4}{x} \\ $$$${water}\:\mathrm{3}{x}+\mathrm{7} \\ $$$${New}\:{ratio}\:\mathrm{4}{x}:\mathrm{3}{x}+\mathrm{7}=\mathrm{3}:\mathrm{4} \\ $$$$\:\:\:\:\:\:\mathrm{16}{x}=\mathrm{9}{x}+\mathrm{21} \\ $$$$\:\:\:\:\:\:\:\:{x}=\mathrm{3} \\ $$$${Amount}\:{of}\:{alcohol}\:\mathrm{4}{x}=\mathrm{4}\left(\mathrm{3}\right)=\mathrm{12}\:\left({liters}\right) \\ $$