Question Number 224013 by efronzo1 last updated on 14/Aug/25
Commented by efronzo1 last updated on 14/Aug/25
$$\mathrm{Given}\:\mathrm{AB}\:\mathrm{is}\:\mathrm{diameter}\:,\:\angle\mathrm{AOD}=\mathrm{22}° \\ $$$$\:\mathrm{and}\:\angle\mathrm{BCD}=\:\mathrm{p}°. \\ $$$$\:\mathrm{Find}\:\mathrm{p}. \\ $$
Answered by A5T last updated on 14/Aug/25
$$\angle\mathrm{ACB}=\mathrm{90}°;\:\angle\mathrm{ACD}=\frac{\mathrm{22}°}{\mathrm{2}}=\mathrm{11}° \\ $$$$\Rightarrow\angle\mathrm{BCD}=\angle\mathrm{ACB}+\angle\mathrm{ACD}=\mathrm{101}° \\ $$