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dy-dx-y-6-2x-2-2xy-5-x-2-y-2-




Question Number 224036 by Buck2233Henry last updated on 15/Aug/25
 (dy/dx)=((y^6 −2x^2 )/(2xy^5 +x^2 y^2 ))
$$\:\frac{{dy}}{{dx}}=\frac{{y}^{\mathrm{6}} −\mathrm{2}{x}^{\mathrm{2}} }{\mathrm{2}{xy}^{\mathrm{5}} +{x}^{\mathrm{2}} {y}^{\mathrm{2}} } \\ $$

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