Question Number 224049 by MASANJAJJ last updated on 16/Aug/25
Answered by RedstoneGG4 last updated on 17/Aug/25
$${O}\:=\:\left(\mathrm{0},\mathrm{0}\right) \\ $$$$ \\ $$$${T}\left({O}\right)\:=\:\left(\mathrm{3},-\mathrm{2}\right) \\ $$$${S}\left({O}\right)\:=\:\left(-\mathrm{2},\mathrm{1}\right) \\ $$$$\left(\mathrm{a}\right)\:\left({S}\:\circ\:{T}\right)\left({O}\right)\:=\:\left(\mathrm{1},-\mathrm{1}\right) \\ $$$$\left(\mathrm{b}\right)\:\left({T}\:\circ\:{S}\right)\left({O}\right)\:=\:\left(\mathrm{1},-\mathrm{1}\right) \\ $$$$\left(\mathrm{c}\right)\:\left({T}\:\circ\:{T}\right)\left({O}\right)\:=\:\left(\mathrm{6},-\mathrm{4}\right) \\ $$$$ \\ $$$${T}\left({O}\right)\:=\:\left(-\mathrm{2},\mathrm{3}\right) \\ $$$$\left({S}\:\circ\:{T}\right)\left({O}\right)\:=\:{O} \\ $$$${P}\:\in\:\mathbb{R}^{\mathrm{2}} :\:{S}\left({P}\right)\:=\:\left({P}_{{x}} +\mathrm{2},\:{P}_{{y}} −\mathrm{3}\right)\:\left\{{P}\:+\:\left(\mathrm{2},-\mathrm{3}\right)\right\} \\ $$$$ \\ $$$$\mathrm{Am}\:\mathrm{I}\:\mathrm{correct}? \\ $$