Question Number 224121 by fantastic last updated on 21/Aug/25
Answered by mr W last updated on 21/Aug/25
$${R}=\frac{\mathrm{1}}{\mathrm{2}\sqrt{\frac{\mathrm{1}}{\mathrm{10}×\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}×\mathrm{10}}}−\frac{\mathrm{1}}{\mathrm{10}}−\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{2}}}=\mathrm{15} \\ $$$$\pi{R}^{\mathrm{2}} =\mathrm{225}\pi\:\checkmark \\ $$
Commented by fantastic last updated on 21/Aug/25
$${Bruh}\:{I}\:{generalized}\:{the}\:{question} \\ $$$${please}\:{tell}\:{me}\:{if}\:{i}\:{have}\:{done}\:{anything} \\ $$$${wrong}. \\ $$