Question Number 224608 by fantastic last updated on 21/Sep/25
Commented by fantastic last updated on 21/Sep/25
$$\measuredangle{EFD}=? \\ $$
Answered by som(math1967) last updated on 21/Sep/25
Commented by som(math1967) last updated on 21/Sep/25
$${FH}={EH}\Rightarrow\angle{FEH}=\angle{EFH}={x}\:{let} \\ $$$${FH}={HD}\Rightarrow\angle{HFD}=\angle{HDF}={y}\:{let} \\ $$$$\therefore{x}+{x}+{y}+{y}=\mathrm{180} \\ $$$$\Rightarrow{x}+{y}=\mathrm{90}\:\therefore\angle{EFD}=\mathrm{90} \\ $$
Commented by fantastic last updated on 21/Sep/25
$${thank}\:{you}\:{sir} \\ $$
Commented by fantastic last updated on 21/Sep/25
$${sir}\:{are}\:{you}\:{teaching}\:{math}\:{from} \\ $$$$\mathrm{1967} \\ $$
Commented by som(math1967) last updated on 22/Sep/25
$${No}\:\:\underline{\underbrace{\lesseqgtr}} \\ $$
Commented by fantastic last updated on 22/Sep/25
$${Ooooo} \\ $$