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Question-224641




Question Number 224641 by Mingma last updated on 23/Sep/25
Answered by mr W last updated on 07/Oct/25
(a)  p=(4/C_5 ^(52) )=(1/(649 740))  (b)  p=((C_3 ^(26) ×C_2 ^(26) )/C_5 ^(52) )=((1625)/(4998))≈0.325  (c)  □♠□□♠  ......  (d)  p=((4×3×2×C_1 ^(13) ×C_2 ^(13) ×C_2 ^(13) )/C_5 ^(52) )=((3042)/(4165))≈0.73
$$\left({a}\right) \\ $$$${p}=\frac{\mathrm{4}}{{C}_{\mathrm{5}} ^{\mathrm{52}} }=\frac{\mathrm{1}}{\mathrm{649}\:\mathrm{740}} \\ $$$$\left({b}\right) \\ $$$${p}=\frac{{C}_{\mathrm{3}} ^{\mathrm{26}} ×{C}_{\mathrm{2}} ^{\mathrm{26}} }{{C}_{\mathrm{5}} ^{\mathrm{52}} }=\frac{\mathrm{1625}}{\mathrm{4998}}\approx\mathrm{0}.\mathrm{325} \\ $$$$\left({c}\right) \\ $$$$\Box\spadesuit\Box\Box\spadesuit \\ $$$$…… \\ $$$$\left({d}\right) \\ $$$${p}=\frac{\mathrm{4}×\mathrm{3}×\mathrm{2}×{C}_{\mathrm{1}} ^{\mathrm{13}} ×{C}_{\mathrm{2}} ^{\mathrm{13}} ×{C}_{\mathrm{2}} ^{\mathrm{13}} }{{C}_{\mathrm{5}} ^{\mathrm{52}} }=\frac{\mathrm{3042}}{\mathrm{4165}}\approx\mathrm{0}.\mathrm{73} \\ $$

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