K-0-sinx-coshx-e-2x-e-4x-dx- Tinku Tara October 3, 2025 Integration 0 Comments FacebookTweetPin Question Number 224771 by mnjuly1970 last updated on 03/Oct/25 $$ \\ $$$$\:\:{K}=\int_{\mathrm{0}} ^{\:\infty} \frac{{sinx}}{{coshx}}\:\left({e}^{−\mathrm{2}{x}} −{e}^{−\mathrm{4}{x}} \right){dx}=?\:\:\:\:\: \\ $$$$\:\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: log-5-5-1-x-125-log-5-6-1-1-2x-x-Next Next post: 2x-3-x-3-3-3-x-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.