Question Number 224814 by fantastic last updated on 05/Oct/25
Answered by mr W last updated on 05/Oct/25
$${v}_{{D}} =\frac{{v}_{{A}} +{v}_{{E}} }{\mathrm{2}}=\frac{\mathrm{4}+\mathrm{0}}{\mathrm{2}}=\mathrm{2}\:{m}/{s} \\ $$$${v}_{{C}} =\frac{{v}_{{B}} +{v}_{{D}} }{\mathrm{2}}=\frac{\mathrm{6}+\mathrm{2}}{\mathrm{2}}=\mathrm{4}\:{m}/{s}\:\checkmark \\ $$
Commented by mr W last updated on 05/Oct/25
Commented by mr W last updated on 05/Oct/25
$${generally}: \\ $$$${V}_{{P}} ={V}_{{R}} +\Delta{V} \\ $$$${V}_{{Q}} ={V}_{{R}} −\Delta{V} \\ $$$$\Rightarrow{V}_{{P}} +{V}_{{Q}} =\mathrm{2}{V}_{{R}} \\ $$$$\Rightarrow{V}_{{R}} =\frac{{V}_{{P}} +{V}_{{Q}} }{\mathrm{2}} \\ $$