Menu Close

Question-226044




Question Number 226044 by Jubr last updated on 18/Nov/25
Answered by mr W last updated on 19/Nov/25
1C_(50) ^(1000) +2C_(49) ^(999) +3C_(48) ^(998) +...+51C_0 ^(950)
$$\mathrm{1}{C}_{\mathrm{50}} ^{\mathrm{1000}} +\mathrm{2}{C}_{\mathrm{49}} ^{\mathrm{999}} +\mathrm{3}{C}_{\mathrm{48}} ^{\mathrm{998}} +…+\mathrm{51}{C}_{\mathrm{0}} ^{\mathrm{950}} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *