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Question Number 226777 by Spillover last updated on 14/Dec/25
Show that   ∫_0 ^1 x^2 (1+x^2 )^(−1) dx=((4−π)/4)  Hence by using Simpson^′ s  rule find the value  of π  correct to 4 decimal places
$${Show}\:{that} \\ $$$$\:\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{\mathrm{2}} \left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{−\mathrm{1}} {dx}=\frac{\mathrm{4}−\pi}{\mathrm{4}} \\ $$$${Hence}\:{by}\:{using}\:{Simpson}^{'} {s} \\ $$$${rule}\:{find}\:{the}\:{value}\:\:{of}\:\pi \\ $$$${correct}\:{to}\:\mathrm{4}\:{decimal}\:{places} \\ $$

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