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Evaluate-x-2-2x-1-2x-3-3x-2-2x-dx-




Question Number 226818 by Spillover last updated on 16/Dec/25
Evaluate  ∫((x^2 +2x−1)/(2x^3 +3x^2 −2x))dx
$${Evaluate} \\ $$$$\int\frac{{x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{1}}{\mathrm{2}{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}{x}}{dx} \\ $$
Answered by Frix last updated on 16/Dec/25
=(1/2)∫(dx/x)−(1/(10))∫(dx/(x+2))+(1/5)∫(dx/(2x−1))=  =(1/(10))ln ∣((x^5 (2x−1))/(x+2))∣ +C
$$=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}}−\frac{\mathrm{1}}{\mathrm{10}}\int\frac{{dx}}{{x}+\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{5}}\int\frac{{dx}}{\mathrm{2}{x}−\mathrm{1}}= \\ $$$$=\frac{\mathrm{1}}{\mathrm{10}}\mathrm{ln}\:\mid\frac{{x}^{\mathrm{5}} \left(\mathrm{2}{x}−\mathrm{1}\right)}{{x}+\mathrm{2}}\mid\:+{C} \\ $$
Commented by Spillover last updated on 16/Dec/25
thanks
$${thanks} \\ $$

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