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Question-226830




Question Number 226830 by Estevao last updated on 16/Dec/25
Answered by TonyCWX last updated on 17/Dec/25
27 = 3^3  =^2 3  ^2 x = 2  x^x =2  For x^x =a, x=e^(W(ln(2))) , where W(x) = Lambert W Function  x = e^(W(ln(2)))
$$\mathrm{27}\:=\:\mathrm{3}^{\mathrm{3}} \:=\:^{\mathrm{2}} \mathrm{3} \\ $$$$\:^{\mathrm{2}} {x}\:=\:\mathrm{2} \\ $$$${x}^{{x}} =\mathrm{2} \\ $$$$\mathrm{For}\:{x}^{{x}} ={a},\:{x}={e}^{{W}\left(\mathrm{ln}\left(\mathrm{2}\right)\right)} ,\:\mathrm{where}\:{W}\left({x}\right)\:=\:\mathrm{Lambert}\:\mathrm{W}\:\mathrm{Function} \\ $$$${x}\:=\:{e}^{{W}\left(\mathrm{ln}\left(\mathrm{2}\right)\right)} \\ $$

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