Question Number 226829 by Estevao last updated on 16/Dec/25
Answered by Estevao last updated on 17/Dec/25
$${Good} \\ $$
Answered by mr W last updated on 17/Dec/25
Commented by mr W last updated on 17/Dec/25
$${R}^{\mathrm{2}} =\left({R}−{a}\right)^{\mathrm{2}} +\left(\mathrm{2}{a}\right)^{\mathrm{2}} \\ $$$$\mathrm{2}{R}=\mathrm{5}{a} \\ $$$$\Rightarrow\frac{{a}}{{R}}=\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\frac{{green}}{{yellow}}=\left(\frac{{a}}{{R}}\right)^{\mathrm{2}} =\frac{\mathrm{4}}{\mathrm{25}} \\ $$$${X}=\frac{\mathrm{4}}{\mathrm{25}}×\mathrm{25}=\mathrm{4}\:{u}^{\mathrm{2}} \\ $$